Algebraeasy · Past Paper
If P(x) = x^2 + kx + 4 and P(1) = 0, what is the value of k?
A-5
B5
C-4
D4
✓ Correct Answer: A — -5
P(1) = 1^2 + k(1) + 4 = 1 + k + 4 = 5 + k. Since P(1)=0, k = -5.
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✓ Correct Answer: A — -5
P(1) = 1^2 + k(1) + 4 = 1 + k + 4 = 5 + k. Since P(1)=0, k = -5.
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