Algebrahard · Past Paper
Find the value of k for which the equation 4x^2 - 2(k+1)x + (k+4) = 0 has equal roots.
A5, -3
B3, -5
C4, -4
D0, 5
✓ Correct Answer: A — 5, -3
D = [2(k+1)]^2 - 4(4)(k+4) = 0 → 4(k^2+2k+1) - 16k - 64 = 0 → k^2 - 2k - 15 = 0 → k=5, -3.
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