Algebramedium · Past Paper
If the discriminant of x^2 + bx + 1 = 0 is negative, then:
Ab^2 < 4
Bb^2 > 4
Cb^2 = 4
Db < 2
✓ Correct Answer: A — b^2 < 4
D = b^2 - 4(1)(1) < 0 → b^2 - 4 < 0 → b^2 < 4.
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✓ Correct Answer: A — b^2 < 4
D = b^2 - 4(1)(1) < 0 → b^2 - 4 < 0 → b^2 < 4.
Share this question