Arithmetichard · Past Paper
A man buys some oranges at 5 for a rupee and an equal number at 4 for a rupee. He sells the whole lot at 9 for 2 rupees. What is his gain or loss %?
A1.23% loss
B1.23% gain
CNo profit no loss
D2% loss
✓ Correct Answer: A — 1.23% loss
Let he buys 20 of each. Total CP = 4+5 = 9. Total SP = (40/9)*2 = 80/9 = 8.88. Loss = 9 - 8.88 = 0.11. Loss % = (0.11/9)*100 = 1.23%.
Share this question
More from Arithmetic
- If a number is reduced by 40%, it becomes 480. What is the number?
- After allowing a discount of 10% on the marked price, a trader still gains 20%. If the marked price is Rs. 800, what is the cost price?
- Divide Rs 600 in the ratio 2:3.
- A man gave 35% of his money to his son and 25% to his daughter. He has Rs. 2000 left. How much did he have originally?
- A man's salary was reduced by 50%. Again the reduced salary was increased by 50%. Find his loss in percentage.