Arithmetichard · Past Paper
If $a/b = c/d = e/f = 3$, then $(2a^2 + 3c^2 + 4e^2) / (2b^2 + 3d^2 + 4f^2)$ is:
A3
B9
C1/3
D27
✓ Correct Answer: B — 9
a=3b, c=3d, e=3f. Substitute: (2(3b)^2 + 3(3d)^2 + 4(3f)^2) / (...) = 9(2b^2+3d^2+4f^2) / (...) = 9.
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