Geometryhard · Past Paper
If the sum of the areas of two circles with radii r1 and r2 is equal to the area of a circle of radius R, then:
Ar1 + r2 = R
Br1^2 + r2^2 = R^2
Cr1^2 + r2^2 < R^2
Dr1 + r2 < R
✓ Correct Answer: B — r1^2 + r2^2 = R^2
pi*r1^2 + pi*r2^2 = pi*R^2 leads directly to the Pythagorean-like relationship.
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