Geometrymedium · Past Paper
In a circle, two chords AB and CD intersect at E. If AE = 4, EB = 3, and CE = 2, find ED.
A4
B5
C6
D8
✓ Correct Answer: C — 6
Property of chords: AE * EB = CE * ED => 4 * 3 = 2 * ED => 12 = 2 * ED => ED = 6.
Share this question
More from Geometry
- The area of the circumcircle of an equilateral triangle with side 6 is:
- If a chord subtends an angle of 120 degrees at the center of a circle of radius 12 cm, find the length of the chord.
- Which of the following is always true for the orthocenter of an obtuse triangle?
- In a right triangle, the length of the median to the hypotenuse is 5 cm. What is the length of the hypotenuse?
- What is the angle subtended by a diameter at any point on the circumference?