Geometryhard · Past Paper
Three circles of radius 1 cm touch each other externally. What is the area of the region enclosed between them?
Asqrt(3) - pi/2
Bsqrt(3) - pi
C2 * sqrt(3) - pi
Dsqrt(3) - 3 * pi
✓ Correct Answer: A — sqrt(3) - pi/2
Triangle formed by centers is equilateral with side 2. Area = sqrt(3)/4 * 2^2 = sqrt(3). Area of 3 sectors (60 deg each) = 3 * (60/360) * pi * 1^2 = pi/2. Enclosed area = sqrt(3) - pi/2.
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