Geometrymedium · Past Paper
Find the equation of a circle with center (2, -3) and radius 5.
Ax^2 + y^2 - 4x + 6y - 12 = 0
Bx^2 + y^2 + 4x - 6y - 12 = 0
Cx^2 + y^2 - 4x + 6y + 12 = 0
Dx^2 + y^2 - 2x + 3y - 25 = 0
✓ Correct Answer: A — x^2 + y^2 - 4x + 6y - 12 = 0
(x-2)^2 + (y+3)^2 = 25 => x^2-4x+4 + y^2+6y+9 = 25 => x^2+y^2-4x+6y-12=0.
Share this question
More from Geometry
- The ratio of the area of a circle to the area of its circumscribed square is:
- If the circumference of a circle is equal to the perimeter of a square, then the ratio of their areas is:
- Find the value of k if the point (k, 3) lies on the line 2x + 3y = 11.
- If (a, 0), (0, b), and (1, 1) are collinear, then 1/a + 1/b = ?
- Find the equation of a line passing through (1, -2) and having a slope of 3.