Geometryhard · Past Paper
Find the equation of the locus of a point which moves such that its distance from the y-axis is twice its distance from the x-axis.
Ax = 2y
By = 2x
Cx^2 = 4y^2
Dy^2 = 4x^2
✓ Correct Answer: C — x^2 = 4y^2
Distance from y-axis is |x|, distance from x-axis is |y|. |x| = 2|y| => x^2 = 4y^2.
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