Geometrymedium · Past Paper
The pair of lines represented by x^2 - 5xy + 6y^2 = 0 are:
Ax - 2y = 0 and x - 3y = 0
Bx + 2y = 0 and x + 3y = 0
Cx - y = 0 and x - 6y = 0
D2x - y = 0 and 3x - y = 0
✓ Correct Answer: A — x - 2y = 0 and x - 3y = 0
Factoring the quadratic: x^2 - 2xy - 3xy + 6y^2 = x(x - 2y) - 3y(x - 2y) = (x - 2y)(x - 3y) = 0.
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