Geometrymedium · Past Paper
The point on the x-axis which is equidistant from (2, -5) and (-2, 9) is:
A(-7, 0)
B(0, 7)
C(7, 0)
D(-6, 0)
✓ Correct Answer: A — (-7, 0)
Let point be (x, 0). (x-2)^2 + (0+5)^2 = (x+2)^2 + (0-9)^2 => x^2-4x+4+25 = x^2+4x+4+81 => -8x = 56 => x = -7.
Share this question
More from Geometry
- Find the equation of a circle with center (2, -3) and radius 5.
- If a chord of length 8 cm is at a distance of 3 cm from the center, what is the radius?
- The distance between (2, 3) and (2, -4) is:
- Which of the following is the general equation of a circle?
- If the arc length of a circle is 1/4 of its circumference, what is the angle subtended at the center?