Geometryhard · Past Paper
In the given figure, if AB || CD, angle ABQ = 40 and angle QCD = 30, find angle BQC.
A10 degrees
B70 degrees
C110 degrees
D150 degrees
✓ Correct Answer: B — 70 degrees
Drawing a line through Q parallel to AB, angle BQC = sum of alternate angles = 40 + 30 = 70.
Share this question
More from Geometry
- The equation x^2 + y^2 = 0 represents:
- If the sector of a circle of radius 6 cm has an angle of 120 degrees, find the perimeter of the sector.
- How many circles can pass through three non-collinear points?
- The radius of the circle 4x^2 + 4y^2 = 100 is:
- Which of the following points is the furthest from the origin?