Trigonometrymedium · Past Paper
A plane flying at 3000 m passes vertically above another plane at an instant when elevations of the two planes from the same point are 60° and 45°. Distance between planes?
A3000(1-1/√3) m
B1000√3 m
C1500 m
D3000(√3-1) m
✓ Correct Answer: A — 3000(1-1/√3) m
d = 3000/tan 60 = 3000/√3 = 1000√3. Height of lower plane = 1000√3 * tan 45 = 1000√3. Difference = 3000 - 1000√3.
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