Trigonometryhard · Past Paper
The angle of elevation of the top of a tower from a point A due south is 30° and from B due east is 45°. If AB = 100 m, find height.
A50√2 m
B50 m
C100 m
D25√10 m
✓ Correct Answer: A — 50√2 m
x = h cot 30 = h√3. y = h cot 45 = h. x² + y² = 100². 3h² + h² = 10000. 4h² = 10000. h = 50 m. No, 50.
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