Trigonometrymedium · Past Paper
The value of sin 15° is:
A(√3 - 1) / 2√2
B(√3 + 1) / 2√2
C1/4
D√3 / 2
✓ Correct Answer: A — (√3 - 1) / 2√2
sin(45-30) = sin 45 cos 30 - cos 45 sin 30 = (1/√2)(√3/2) - (1/√2)(1/2) = (√3-1)/2√2.
Share this question
✓ Correct Answer: A — (√3 - 1) / 2√2
sin(45-30) = sin 45 cos 30 - cos 45 sin 30 = (1/√2)(√3/2) - (1/√2)(1/2) = (√3-1)/2√2.
Share this question