Trigonometryhard · Past Paper
If sec θ + tan θ = x, then sec θ - tan θ is:
Ax
B1/x
C-x
Dx²
✓ Correct Answer: B — 1/x
Since sec²θ - tan²θ = 1, (sec-tan)(sec+tan)=1, so sec-tan = 1/(sec+tan) = 1/x.
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✓ Correct Answer: B — 1/x
Since sec²θ - tan²θ = 1, (sec-tan)(sec+tan)=1, so sec-tan = 1/(sec+tan) = 1/x.
Share this question