Chemistryhard · Past Paper
If the $K_b$ of a base is $10^{-5}$, what is its $pK_b$?
A5
B-5
C10
D9
✓ Correct Answer: A — 5
$pK_b = -log(K_b)$. So, $-log(10^{-5}) = 5$.
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✓ Correct Answer: A — 5
$pK_b = -log(K_b)$. So, $-log(10^{-5}) = 5$.
Share this question