Physicshard · Past Paper
In a hydraulic machine, the area of the smaller piston is 0.01 m^2 and the larger piston is 1 m^2. If 10 N force is applied to the small piston, the force on the large piston is:
A100 N
B1000 N
C10,000 N
D0.1 N
✓ Correct Answer: B — 1000 N
F2/A2 = F1/A1. F2 = (F1 * A2) / A1 = (10 * 1) / 0.01 = 1000 N.
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