Physicsmedium · Past Paper
A ball is thrown up and it reaches a height of 80m. What was its initial velocity? (g=10 m/s^2)
A40 m/s
B20 m/s
C80 m/s
D10 m/s
✓ Correct Answer: A — 40 m/s
v^2 = u^2 - 2gh => 0 = u^2 - 2*10*80 => u^2 = 1600 => u = 40 m/s.
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