Physicsmedium · Past Paper
An object covers 1/4th of a circular path of radius r. The magnitude of its displacement is:
Aπr/2
Br√2
Cr
D2r
✓ Correct Answer: B — r√2
The displacement is the chord length. Using Pythagoras theorem, d = √(r^2 + r^2) = r√2.
Share this question
More from Physics
- A car starting from rest moves with an acceleration of 4 m/s^2. What is its velocity after 10s?
- A point moves with uniform acceleration and v1, v2, v3 denote average velocities in three successive intervals of time t1, t2, t3. Which of the following is correct?
- When a bus starts suddenly, passengers tend to fall backwards due to:
- A ball is dropped from a building and reaches the ground in 3s. What is the height of the building? (g = 10 m/s^2)
- Which of the following remains constant in uniform circular motion?