Physicshard · Past Paper
The distance x of a particle varies with time t as x = at^2 - bt^3. The acceleration of the particle will be zero at time t equals to:
Aa/b
Ba/3b
C3b/a
DZero
✓ Correct Answer: B — a/3b
v = 2at - 3bt^2, acc = 2a - 6bt. Acc=0 => 6bt = 2a => t = a/3b.
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