Physicsmedium · Past Paper
A spring is compressed by 0.1 m. If the spring constant is 100 N/m, the energy stored is:
A10 J
B1 J
C0.5 J
D5 J
✓ Correct Answer: C — 0.5 J
Elastic PE = 1/2 kx^2 = 1/2 * 100 * (0.1)^2 = 0.5 J.
Share this question
✓ Correct Answer: C — 0.5 J
Elastic PE = 1/2 kx^2 = 1/2 * 100 * (0.1)^2 = 0.5 J.
Share this question