Physicshard · Past Paper
If a body of mass m starts falling from point A at height h, what is its velocity at point B which is at height h/2?
Asqrt(gh)
Bsqrt(2gh)
Csqrt(gh/2)
D2sqrt(gh)
✓ Correct Answer: A — sqrt(gh)
Loss in PE = Gain in KE. mg(h - h/2) = 1/2 mv^2 => mgh/2 = 1/2 mv^2 => v = sqrt(gh).
Share this question
More from Physics
- A body is thrown vertically upwards with velocity u. The maximum height reached is:
- If the cost of electricity is Rs. 10 per unit, how much does it cost to run a 2kW heater for 5 hours?
- A man carries a heavy suitcase on his head and waits for a bus on a horizontal platform. The work done by him is:
- A bus starting from rest moves with a uniform acceleration of 0.1 m/s^2 for 2 minutes. Find the speed acquired.
- The formula for pressure exerted by a liquid column is: